1. If Rs. 10 be allowed as true discount on a bill of Rs. 110 due at the end of a certain time, then the discount allowed on the same sum due at the end of double the time is:
A. Rs. 20 B. Rs. 21.81 C. Rs. 22 D. Rs. 18.33
Answer: D. Rs. 18.33
Explanation:
S.I. on Rs. (110 ? 10) for a certain time = Rs. 10. S.I. on Rs. 100 for double the time = Rs. 20. T.D. on Rs. 120 = Rs. (120 ? 100) = Rs. 20. T.D. on Rs. 110 = Rs. ( 20/120 x 110) = Rs. 18.33
2. The true discount on a bill due 9 months hence at 16% per annum is Rs. 189. The amount of the bill is:
A. Rs. 1386 B. Rs. 1764 C. Rs. 1575 D. Rs. 2268
Answer: B. Rs. 1764
Explanation:
Let P.W. be Rs. x. Then, S.I. on Rs. x at 16% for 9 months = Rs. 189. x x 16 x 9/12 x 1/100 = 189 or x = 1575. P.W. = Rs. 1575. Sum due = P.W. + T.D. = Rs. (1575 + 189) = Rs. 1764.
3. Rs. 20 is the true discount on Rs. 260 due after a certain time. What will be the true discount on the same sum due after half of the former time, the rate of interest being the same?
A. Rs. 10 B. Rs. 10.40 C. Rs. 15.20 D. Rs. 13
Answer: B. Rs. 10.40
Explanation:
S.I. on Rs. (260 ? 20) for a given time = Rs. 20. S.I. on Rs. 240 for half the time = Rs. 10. T.D. on Rs. 250 = Rs. 10. T.D. on Rs. 260 = Rs. ( 10/250 x 260) = Rs. 10.40
4. A and B can together finish a work in 30 days. They worked at it for 20 days and then B left. The remaining work was done by A alone in 20 more days. A alone can finish the work in?
A. 48 days B. 54 days C. 50 days D. 60 days
Answer: D. 60 days
Explanation:
Work done by A and B in 20 days = (1/30 * 20) = 2/3 Remaining work= ( 1 -2/3) = 1/3 Now,1/3 work is done by A in 20days Whole work will be done by A in (20×3) = 60 days.
5. A can do a certain job in 25 days which B alone can do in 20 days. A started the work and was joined by B after 10 days. The number of days taken in completing the work was
A. 12 and half days B. 15 days C. 14 and 2/9 days D. 16 and 2/3 days
Answer: D. 16 and 2/3 days
Explanation:
Work done by A in l0 days = (1/25) *10 = 2/5. Remaining work = 1 ? (2/5) = 3/5 (A+B)?s 1 days work = (1/25) + (1/20) = 9/100 9/100 work is done by them in 1 day. hence 3/5 work will be done by them in (100/9) * (3/5) = 20/3days. Total time taken = (10 + 20/3) = 16 * (2/3) days.
6. If 10 men or 18 boys can do a piece of work in 15 days, then 25 men and 15 boys together will do twice the work in?
A. 4 and half days B. 8 days C. 9 days D. 36 days
Answer: C. 9 days
Explanation:
10 men = 18boy hence 1 man = 18/10 boys 25 men + 15 boys = (25 * 18/10) + 15 = 60 now more work more days more boys less days1 * 60 * x = 2*18*15 or x = (2*18*15)/60 = 9 days
7. A certain number of men complete a piece of work in 60 days. If there were 8 men more, the work could be finished in 10 days less. How many men were originally there?
A. 30 B. 36 C. 32 D. 40
Answer: D. 40
Explanation:
Originally 1et there be x men. More men, less days (x + 8): x ? 60:50 So, x + 8 / x = 60/50 or x = 40. Hence, there were 40 men, originally.
8. Ram can do a piece of work in 8 days which Shyam can finish in 12 days. If they work at it on alternate days with Ram beginning, in how many days, the work will be finished?
A. 9 and 1/3 B. 9 and 1/24 C. 9 and 1/2 D. 10 and 1/3
Answer: C. 9 and 1/2
Explanation:
(Ram + Shyam)?s 2 days work = (1/8) + (1/12) = 5/24 Their 8 days work = (5/24) * 4 = 5/6 Their 8 days work = (5/6) + (1/8) = 23/24 Remaining work = (1 ? (23/24)) Now it is Shyam?S turn. 1/12 work is done by him in 1 day. 1/24 work is done by him in (12 * (1/24)) = 1/2 day. Total time taken = 9 and half days.
9. Amy has to visit towns B and C in any order. The roads connecting these towns with her home are shown on the diagram. How many different routes can she take starting from A and returning to A, going through both B and C (but not more than once through each) and not travelling any road twice on the same trip?
A. 10 B. 8 C. 6 D. 4
Answer: B. 8
Explanation:
Amy can travel clockwise or anticlockwise on the diagram. Clockwise, she has no choice of route from A to B, a choice of one out of two routes from B to C, and a choice of one out of two routes from C back to A. This gives four possible routes. Similarly, anticlockwise she has four different routes. Total routes = 8
10. A man walking at the rate of 5 km/hr crosses a bridge in 15 minutes. The length of the bridge (in metres) is
A. 600 B. 750 C. 1000 D. 1250
Answer: D. 1250
Explanation: speed = (5×5/18)m/sec = 25/18 m/sec. Distance covered in 15 minutes = (25/18 x 15 x 60)m = 1250 m.
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