# Cisco Placement Papers-Free Download

##

**
**__Cisco Questions and Answers__

Cisco Aptitude Questions :

1. What is the probability of getting at least one six in a single
throw of three unbiased dice?

(1) 1 / 6

(2) 125 / 216

(3) 1 / 36

(4) 81 / 216

(5) 91 / 216

Correct choice is (5) and Correct Answer is 91 / 216

Explanatory Answer:

Every die has got six sides. Each of the sides is numbered from 1 to 6.

When a single unbiased die is thrown you can have six possible
outcomes.

When two dice are thrown simultaneously, the total number of outcomes
will be 6 * 6 = 36

Similarly, when three dice are thrown simultaneously, the total number
of outcomes will be 6*6*6=216.

We need to find out the number of cases in which at least one of the
facing sides shows 6.

At least one means - either one dice or two dice or all three.

Case 1: Let us take the easiest case first - all three dice showing '6'
- There is only one such possibility.

Case 2: The number of cases in which two of the dice show 6 and one of
them is a different number.

For eg an event like 6 6 5 will be one of the outcomes for case 2.

As two of the dice show '6' , it can happen in only one way. The third
die shows a different number, a number other than 6, and it can be any
of the 5 other numbers. Therefore, there will 5 possible options i.e.
(1, 6, 6), (2, 6, 6), (3, 6, 6), (4, 6, 6), (5, 6, 6).

However, each of these possibilities can have three different
arrangements depending upon where the third different digit appears.
For example take (1, 6, 6) case - it will have three options (1, 6, 6),
(6, 1, 6), (6, 6, 1).

Therefore, the total number of events in which 2 of the dice will show
'6' and one will show a different number = 5*3 = 15 cases.

Case 3: When only one of the die shows '6' and the other two show
numbers other than '6'.

The die showing '6' has only one option. The other two dice can have
any of the '5' options. Therefore, the total number of possibilities =
1*5*5 = 25.

However, the die showing '6' can either be the first die or the second
die or the third die.

Therefore, there are a total of 25 * 3 = 75 possibilities.

Total possible outcomes where at least one die shows '6' = Case 1 +
Case 2 + Case 3 = 1 + 15 +75 = 91.

Therefore, the required probability = 91/216

Alternate approach:

Find the number of cases in which none of the digits show a '6'.

i.e. all three dice show a number other than '6', 5 * 5 *5 = 125 cases.

Total possible outcomes when three dice are thrown = 216.

The number of outcomes in which at least one die shows a '6' = Total
possible outcomes when three dice are thrown - Number of outcomes in
which none of them show '6'.

= 216 - 125 = 91.

The required probability = 91/216

2. When two dice are thrown simultaneously, what is the probability
that the sum of the two numbers that turn up is less than 11?

(1) 5 / 6

(2) 11 / 12

(3) 1 / 6

(4) 1 / 12

Correct Answer - (2)

Solution:

Instead of finding the probability of this event directly, we will find
the probability of the non-occurrence of this event and subtract it
from 1 to get the required probability.

Combination whose sum of 12 is (6,6)

Combinations whose sum of 11 is (5,6), (6,5).

Therefore, there are totally 3 occurrences out of 36 occurrences that
satisfy the given condition.

Probability whose sum of two numbers is greater than or equal to 11 = 3
/ 36 = 1 / 12.

Hence probability whose sum of two numbers is lesser than 11 = 1 - 1 /
12 = 11 / 12.

3. The average monthly salary of 12 workers and 3 managers in a factory
was Rs. 600. When one of the manager whose salary was Rs. 720, was
replaced with a new manager, then the average salary of the team went
down to 580. What is the salary of the new manager?

Rs 570

Rs 420

Rs 690

Rs 640

Rs 610

Correct Answer - Rs 420. Choice (2)

Explanatory Answer :

The total salary amount = 15 * 600 = 9000

The salary of the exiting manager = 720.

Therefore, the salary of 12 workers and the remaining 2 managers = 9000
- 720 = 8280

When a new manager joins, the new average salary drops to Rs.580 for
the total team of 15 of them.

The total salary for the 15 people i.e., 12 workers, 2 old managers and
1 new manager = 580 *15 = 8700

Therefore, the salary of the new manager is 9000 - 8700 = 300 less than
that of the old manager who left the company, which is equal to 720 -
300 = 420.

Alternative method :

The average salary dropped by Rs.20 for 15 of them. Therefore, the
overall salary has dropped by 15*20 = 300.

Therefore, the new manager's salary should be Rs.300 less than that of
the old manager = 720 - 300 = 420.

4. If the letters of the word CHASM are rearranged to form 5 letter
words such that none of the word repeat and the results arranged in
ascending order as in a dictionary what is the rank of the word CHASM ?

(1) 24

(2) 31

(3) 32

(4) 30

Correct Answer - (3)

Solution:

The 5 letter word can be rearranged in 5! Ways = 120 without any of the
letters repeating.

The first 24 of these words will start with A.

Then the 25th word will start will CA _ _ _. The remaining 3 letters
can be rearranged in 3! Ways = 6. i.e. 6 words exist that start with
CA.

The next word starts with CH and then A, i.e., CHA _ _. The first of
the words will be CHAMS. The next word will be CHASM.

Therefore, the rank of CHASM will be 24 + 6 + 2 = 32.

5. The time in a clock is 20 minute past 2. Find the angle between the
hands of the clock.

(1) 60 degrees

(2) 120 degrees

(3) 45 degrees

(4) 50 degrees

Correct choice (4). Correct Answer - 50 degrees

Solution:

Time is 2:20. Position of the hands: Hour hand at 2 (nearly).

Minute hand at 4

Angle between 2 and 4 is 60 degrees [(360/12) * (4-2)]

Angle made by the hour hand in 20 minutes is 10 degrees, since it turns
through ˝ degrees in a minute.

Therefore, angle between the hands is 60 degrees - 10 degrees = 50
degrees

6. A 12% stock yielding 10% is quoted at:

A.Rs. 83.33

B.Rs. 110

C.Rs. 112

D.Rs. 120

Answer: Option D

Explanation:

To earn Rs. 10, money invested = Rs. 100.

To earn Rs. 12, money invested = Rs.100x 12= Rs. 120.

10 Market value of Rs. 100 stock = Rs. 120

7. A and B take part in 100 m race. A runs at 5 kmph. A gives B a start
of 8 m and still beats him by 8 seconds. The speed of B is:

A.5.15 kmph

B.4.14 kmph

C.4.25 kmph

D4.4 kmph

Answer: Option B

8.100 oranges are bought at the rate of Rs. 350 and sold at the rate of
Rs. 48 per dozen. The percentage of profit or loss is:

9. What was the day of the week on 28th May, 2006?

A.Thursday

B.Friday

C.Saturday

D.Sunday

Answer: Option D

Explanation:

28 May, 2006 = (2005 years + Period from 1.1.2006 to 28.5.2006)

Odd days in 1600 years = 0

Odd days in 400 years = 0

5 years = (4 ordinary years + 1 leap year) = (4 x 1 + 1 x 2) 6 odd days

Jan. Feb. March April May

(31 + 28 + 31 + 30 + 28 ) = 148 days

148 days = (21 weeks + 1 day) 1 odd day.Total number of odd days = (0 +
0 + 6 + 1) = 7 0 odd day.Given day is Sunday.

10. The H.C.F. of two numbers is 11 and their L.C.M. is 7700. If one of
the numbers is 275, then the other is:

A.279

B.283

C.308

D.318

Answer: Option C

Other number =11 x 7700 = 308.275

11. How many digits will be there to the right of the decimal point in
the product of 95.75 and .02554 ?

A.5

B.6

C.7

D.None of these

Answer: Option B

Explanation:

Sum of decimal places = 7.

Since the last digit to the extreme right will be zero (since 5 x 4 =
20), so there will be 6 significant digits to the right of the decimal
point.

12. One pipe can fill a tank three times as fast as another pipe. If
together the two pipes can fill the tank in 36 minutes, then the slower
pipe alone will be able to fill the tank in:

A.81 min.

B.108 min.

C.144 min.

D.192 min.

Answer: Option C

13. A man purchased a cow for Rs. 3000 and sold it the same day for Rs.
3600, allowing the buyer a credit of 2 years. If the rate of interest
be 10% per annum, then the man has a gain of:

A 0%

B.5%

C.7.5%

D.10%

Answer: Option A

Explanation:

C.P. = Rs. 3000.

S.P. = Rs.3600 x 100

= Rs. 3000.

100 + (10 x 2)

Gain = 0%.

14. Find out the wrong number in the series.

6, 12, 48, 100, 384, 768, 3072

A.768

B.384

C.100

D.48

E.12

Answer: Option C

Explanation:

Each even term of the series is obtained by multiplying the previous
term by 2.

2nd term = (1st term) x 2 = 6 x 2 = 124th term = (3rd term) x 2 = 48 x
2 = 96.6th term = (5th term) x 2 = 384 x 2 =768. 4th term should be 96
instead of 100

15. David gets on the elevator at the 11th floor of a building and
rides up at the rate of 57 floors per minute. At the same time, Albert
gets on an elevator at the 51st floor of the same building and rides
down at the rate of 63 floors per minute. If they continue travelling
at these rates, then at which floor will their paths cross ?

A.19

B.28

C.30

D.37

Answer: Option C

** **

__SECTION 2:__

** **

**1. main()**

** { fork();**

** fork();**

** fork();**

** printf("hello");**

** }**

**How many times it will print hello?**

** **

**2: char A[5,6] How many bytes it requires?**

** **

**3:Bridges are used in which layer?**

** **

**4.Bigendian means**

**a)lower byte stored in lower address**

**b)lower byte stored in higher address**

**
one of these is correct.u can verify in Any micro processor book.
**

** **

**
5: #define mmx 10+10
**

printf"%d",mmx*mmx);

** **

**6: main()**

** { j=0**

** for(i=0;i<10;i++)**

** { j+=i; }**

** }**

**what is the value of i & j at the end of the loop**

**ans: 10,46**

** **

**
7: Regular expression with 2 consecutive 1's and all string of 0's and
1's
**

** **

**8: dead lock conditions 1 question**

** **

**
9: selective repeat widow size of sender & receiver 1 question.
**

** **

**10;Balanced trees 1 question**

** **

** **

## Source: Contents are provided by Technicalsymposium Google Group Members.

Disclaimer: All the above contents are provided by technicalsymposium.com Google Group members.

Further, this content is not intended to be used for commercial purpose. Technicalsymposium.com is not liable/responsible for any copyright issues.