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Software Companies Placement Papers With Answers-Apps Associates -Free Download

1. When Rajeev was born, his father was 32 years older than his brother and his mother was 25 years older than his sister. If Rajeev's brother is 6 years older than Rajeev and his mother is 3 years younger than his father, how old was Rajeev's sister when Rajeev was born?

A. 10 years

B. 12 years

C. 15 years

D. 8 years

Explanation:

Let, Rajiv's brother is x years old.

Then his father is 6+32=38 when he was born.

And his mother is 3 years younger than his father.

So his mother was 35 years old when Rajeev was born.

And his sister is 25 years younger than his mother.

So, Rajeev’s sister was 10 years old when Rajeev was born.

2. Radha bought a watch for Rs. 144 and got a percentage of profit equal to the cost price of the watch. What is the cost price of the watch?

A. Rs. 72

B. Rs. 78

C. Rs. 80

D. Rs. 90

Explanation:

Given, SP=144, CP=x and profit %=x

Cost Price = (100/ (100+gain%))*S.P.

=> x=(100/100+x) *144

=> x^2+100x=14400

=> x^2+180x-80x-14400=0

=> (x+180) (x-80) =0

=> x=-180. [It -ve value, so rejected]

=> x=80.

3. In how many ways can 5 members be selected out of 10 members, so that any two particular members must always be excluded?

A. 52

B. 56

C. 60

D. 64

Explanation:

Given, two particular members must be excluded, so member=10-2=8

Hence, the answer will be = 8! /5! (8-5)! = 8 * 7 * 6 * 5! /5! * 3! = 8 * 7 * 6/3 * 2 * 1 = 8 * 7 = 56.

4. In a 100m race, B bet C by 25m and A bet B by 20m. Then A will beat C by what meters?

A. 60 m

B. 40 m

C. 50m

D. 20 m

Explanation:

According to the question,

A: B=100:80, and

B:C=100:75.

Now,

A:C=(A/B) *(B/C) =100/60.

Hence, A will beat C by 100-60=40m.

5. Krishna bought some wheat at Rs. 10 per kilogram. He buys 2 kg wheat from a ration shop at the rate of Rs. 8 per kilogram. He mixes the two and sells at Rs. 11 per kilogram. He makes 25% profit. What is the ratio of non-ration to ration wheat?

option

A. 1:4

B. 1:5

C. 5:1

D. None of the above

Explanation:

Given, Selling Price per kg=11rs

and, CP per kg=11(4/5) =44/5

Hence, the required ratio = ((44/5)-8)/ (10-(44/5)) = 2:3.

6. A got Rs. 150 more on sum amount as a rate of 3%, then what is the amount?

A. 4500

B. 5000

C. 3254

D. 3500

Explanation:

Amount = S.I + Principal Amount

SI = PRT/100

Let P= x.

Amount = 150 + x;

Therefore S. I= 150

=> x*3*1/100 = 150 (Taking T=1year)

Amount that is principal amount is x= 5000.

7. Mr. Roy is twelve years more than twice the age of his son at present. After twelve years, he will be thrice as old as his son. What is the age of Mr. Roy at present?

A. 32

B. 36

C. 26

D. 40

Explanation:

Let son's age be x.

Then Roy’s age =2x + 12.

After 12yrs, son's age=x+12 & Roy’s age=2x+12+12

Then, we get the equation as

=> 3(x + 12) = 2x + 12 + 12.

=> x = 12

Hence, Roy's age = 36.

8. A quantity of tea is sold at Rs. 5.75 per kilogram. The total gain by selling the tea at this rate is Rs. 60. Find the quantity of tea being sold if a profit of 15% is made on the deal.

A. 90kg

B. 60kg

C. 80kg

D. 75kg

Explanation:

Let the total cost price of tea is x.

Then total profit at a rate of 15% is=(15x/100)

According to question,

=> 15x/100=60

So, x=400

Cost Price of the tea is 400.so total selling price will be= (400+60) =460.

So, the quantity of the tea will be= (460/5.75) =80kg.

9. The sum of 3rd and 9th term of an A.P is 8. Find the sum of the first 11 terms of the progression.

A. 44

B. 22

C. 54

D. None of the above

Explanation:

Given, the third term t3 = a + 3d

The ninth term t9 = a + 8d

Now, t3 + t9 = 2a + 10d = 8

Sum of first 11 terms of an AP is given by

=> (11/2) (2a + 10d)

=> (11/2) (8)

=> 88/2

=> 44.

10. Determine the metal required to make a 21 m long pipe if its inner and outer diameter are 12 m and 10 m respectively.

A. 2904 m3

B. 2534 m3

C. 2843 m3

D. 2647 m3

Explanation:

Formula: Volume of a hollow cylinder=pi*h*(R2-r2)

=> 22/7 * 21m*(144-100) m2

=> 66*44 m3

=> 2904 m3

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