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Software Companies Placement Papers- -Free Download

Software Companies Placement Papers With Answers- -Free Download

Direction for Question 1,2,3,4 and 5: Study the following information and answer the following questions.

It is very easy to remember the ID number of my ATM card which is a nine digit number and every digit is distinct. If i tell you some clues then you will be able to find it.Consider my numer as PQRSTUVWX corresponing to 1 to 9 digits though not repository .The Id is divisible by 9. if you delete the digit at its units place, the remaining 8 digit number of my ID is divisible by 8. If you again delete the last digit of the 8 digit number the remaining 7 digit number is divisible by 7 and the process goes on.

1) What is the sum of the digits of the ID number of my ATM card?
a) 55 b) 45 c) 90 d) Cannot be determined

2) Find the first five digits from the Following.

3) Find the last five digits from the following.

4) Find the nine digit id of card.

5) Which number does letter R represents

6) A hash table can store a maximum of 10 records, currently there are records in location 1, 3,4,7,8,9,10. The probability of a new record going into location 2, with hash functions resolving collisions by linear probing is
a. 0.1 b. 0.6 c. 0.2 d. 0.5

7) While using HTTP GET request the information is transferred as part of

a. url b.body c. cannot transferred

Cool Which data structure is useful in transferring a given graph by breadth first search.

a. heap b. linkedlist c. array d. stack e. queue

9) A complete n- array tree in which each node has n children or no children, let i be the number of internal nodes and L be the number of leaves in a complete n- array tree. If L=41 and i=10 what is the value of n.

a. 3 b. 6 c. 4

10) int(* fun()) [row][ Col];

What should be the statement the for the above declarations

a.fun() points to a two dimensional array
b.pointer *fun() points to a two dimensional array
c.pointer *fun() points to 1-dimensional array

11) The angles of elevation of the top of a tower from two points at distances M and N meters are complementary, if the two points and the base of the tower are on the same straight line then the height of the tower is

A.mn B. M/N C. square root of MN D. none of the above

12) A retailer has n stones by which he can mesure or(weigh)all the quantities from (1kg to 121kg in integer only) keeping these stones on either side of the balance what is the minimum value of n.

A.3 B.4 C. 5 D. 11

13) Four jobs to be executed on a single processor system arrive at time of in the order ABCD, their burst cpu times requirements are 4,1,8,1 time units respectively the completion time of A under round robin scheduling with time slice of one time unit is

A. 10 B. 4 C. 8 D.9

14) Fill the missing number

0, 3, 2, 30, ? , 105,168.

15) Two person each make a single throw with a pair of dice. The probability that the sum of numbers if the dice of their throws are unequal is

A. 575/648 B. 273/432 c. 264/816.

16) ABCD is a parallelogram and E is the middle point of side AD EC meets BD at O. If the area if the parallelogram is 24 units then the area of EOD is ?

17) In the adjoining figure ABCD is a Cyclic quadrilateral with AC perpendicular to BD and AC meets BD at E. given that EA2+EB2+EC2=100cm. find the radius of the circumscribed circle

1Cool Speaker’s _____ is easy to hear but difficult to _________ it.
a. idea/implement b. words/practice

19) What will be the output of the following program

#include
int main()
{
int m=10,p;
p=incre(incre (incre (++) incre) incre)
Printf(“%d”, *&P);
return 0;
}
incre (int m)
{
m+=2;
return(m-2);
}

1. Base class has some virtual method and derived class has a method with the same name. If we initialize the base class pointer with derived
object,. calling of that virtual method will result in which method being called?

a. Base method
b. Derived method..

Ans. b

2. For the following C program

#define AREA(x)(3.14*x*x)
main()
{float r1=6.25,r2=2.5,a;
a=AREA(r1);
printf("\n Area of the circle is %f", a);
a=AREA(r2);
printf("\n Area of the circle is %f", a);
}

What is the output?

Ans. Area of the circle is 122.656250
Area of the circle is 19.625000

3. What do the following statements indicate. Explain.

  • int(*p)[10]
  • int*f()
  • int(*pf)()
  • int*p[10]

Refer to:
-- Kernighan & Ritchie page no. 122
-- Schaum series page no. 323

4.
void main()
{
int d=5;
printf("%f",d);
}

Ans: Undefined


5.
void main()
{
int i;
for(i=1;i<4,i++)
switch(i)
case 1: printf("%d",i);break;
{
case 2:printf("%d",i);break;
case 3:printf("%d",i);break;
}
switch(i) case 4:printf("%d",i);
}

Ans: 1,2,3,4


6.
void main()
{
char *s="\12345s\n";
printf("%d",sizeof(s));
}

Ans: 6


7.
void main()
{
unsigned i=1; /* unsigned char k= -1 => k=255; */
signed j=-1; /* char k= -1 => k=65535 */
/* unsigned or signed int k= -1 =>k=65535 */
if(i<j)
printf("less");
else
if(i>j)
printf("greater");
else
if(i==j)
printf("equal");
}

Ans: less


8.
void main()
{
float j;
j=1000*1000;
printf("%f",j);
}

1. 1000000
2. Overflow
3. Error
4. None

Ans: 4


9. How do you declare an array of N pointers to functions returning
pointers to functions returning pointers to characters?

Ans: The first part of this question can be answered in at least
three ways:

1. char *(*(*a[N])())();

2. Build the declaration up incrementally, using typedefs:

typedef char *pc; /* pointer to char */
typedef pc fpc(); /* function returning pointer to char */
typedef fpc *pfpc; /* pointer to above */
typedef pfpc fpfpc(); /* function returning... */
typedef fpfpc *pfpfpc; /* pointer to... */
pfpfpc a[N]; /* array of... */

3. Use the cdecl program, which turns English into C and vice
versa:

cdecl> declare a as array of pointer to function returning
pointer to function returning pointer to char
char *(*(*a[])())()

cdecl can also explain complicated declarations, help with
casts, and indicate which set of parentheses the arguments
go in (for complicated function definitions, like the one
above).
Any good book on C should explain how to read these complicated
C declarations "inside out" to understand them ("declaration
mimics use").
The pointer-to-function declarations in the examples above have
not included parameter type information. When the parameters
have complicated types, declarations can *really* get messy.
(Modern versions of cdecl can help here, too.)


10. A structure pointer is defined of the type time . With 3 fields min,sec hours having pointers to intergers.
Write the way to initialize the 2nd element to 10.


11. In the above question an array of pointers is declared.
Write the statement to initialize the 3rd element of the 2 element to 10;


12.
int f()
void main()
{
f(1);
f(1,2);
f(1,2,3);
}
f(int i,int j,int k)
{
printf("%d %d %d",i,j,k);
}

What are the number of syntax errors in the above?

Ans: None.


13.
void main()
{
int i=7;
printf("%d",i++*i++);
}

Ans: 56


14.
#define one 0
#ifdef one
printf("one is defined ");
#ifndef one
printf("one is not defined ");

Ans: "one is defined"



15.
void main()
{
int count=10,*temp,sum=0;
temp=&count;
*temp=20;
temp=&sum;
*temp=count;
printf("%d %d %d ",count,*temp,sum);
}

Ans: 20 20 20


16. There was question in c working only on unix machine with pattern matching.


14. what is alloca()

Ans : It allocates and frees memory after use/after getting out of scope


17.
main()
{
static i=3;
printf("%d",i--);
return i>0 ? main():0;
}

Ans: 321


18.
char *foo()
{
char result[100]);
strcpy(result,"anything is good");
return(result);
}
void main()
{
char *j;
j=foo()
printf("%s",j);
}

Ans: anything is good.

19.
void main()
{
char *s[]={ "dharma","hewlett-packard","siemens","ibm"};
char **p;
p=s;
printf("%s",++*p);
printf("%s",*p++);
printf("%s",++*p);
}

Ans: "harma" (p->add(dharma) && (*p)->harma)
"harma" (after printing, p->add(hewlett-packard) &&(*p)->harma)
"ewlett-packard"

20. Output of the following program is

main()
{int i=0;
for(i=0;i<20;i++)
{switch(i)
case 0:i+=5;
case 1:i+=2;
case 5:i+=5;
default i+=4;
break;}
printf("%d,",i);
}
}

a) 0,5,9,13,17
b) 5,9,13,17
c) 12,17,22
d) 16,21
e) Syntax error

Ans. (d)

21. What is the ouptut in the following program

main()
{char c=-64;
int i=-32
unsigned int u =-16;
if(c>i)
{printf("pass1,");
if(c<u)
printf("pass2");
else
printf("Fail2");
}
else
printf("Fail1);
if(i<u)
printf("pass2");
else
printf("Fail2")
}

a) Pass1,Pass2
b) Pass1,Fail2
c) Fail1,Pass2
d) Fail1,Fail2
e) None of these

Ans. (c)

22. What will the following program do?

void main()
{
int i;
char a[]="String";
char *p="New Sring";
char *Temp;
Temp=a;
a=malloc(strlen(p) + 1);
strcpy(a,p); //Line number:9//
p = malloc(strlen(Temp) + 1);
strcpy(p,Temp);
printf("(%s, %s)",a,p);
free(p);
free(a);
} //Line number 15//

a) Swap contents of p & a and print:(New string, string)
b) Generate compilation error in line number 8
c) Generate compilation error in line number 5
d) Generate compilation error in line number 7
e) Generate compilation error in line number 1

Ans. (b)

23. In the following code segment what will be the result of the function,

value of x , value of y
{unsigned int x=-1;
int y;
y = ~0;
if(x == y)
printf("same");
else
printf("not same");
}

a) same, MAXINT, -1
b) not same, MAXINT, -MAXINT
c) same , MAXUNIT, -1
d) same, MAXUNIT, MAXUNIT
e) not same, MAXINT, MAXUNIT

Ans. (a)

24. What will be the result of the following program ?

char *gxxx()
{static char xxx[1024];
return xxx;
}

main()
{char *g="string";
strcpy(gxxx(),g);
g = gxxx();
strcpy(g,"oldstring");
printf("The string is : %s",gxxx());
}

a) The string is : string
b) The string is :Oldstring
c) Run time error/Core dump
d) Syntax error during compilation
e) None of these

Ans. (b)

25. Find the output for the following C program

main()
{
char *p1="Name";
char *p2;
p2=(char *)malloc(20);
while(*p2++=*p1++);
printf("%s\n",p2);
}

Ans. An empty string

26. Find the output for the following C program

main()
{
int x=20,y=35;
x = y++ + x++;
y = ++y + ++x;
printf("%d %d\n",x,y);
}

Ans. 57 94

27. Find the output for the following C program

main()
{
int x=5;
printf("%d %d %d\n",x,x<<2,x>>2);
}

Ans. 5 20 1

28 Find the output for the following C program

#define swap1(a,b) a=a+b;b=a-b;a=a-b;
main()
{
int x=5,y=10;
swap1(x,y);
printf("%d %d\n",x,y);
swap2(x,y);
printf("%d %d\n",x,y);
}
int swap2(int a,int b)
{
int temp;
temp=a;
b=a;
a=temp;
return;
}

Ans. 10 5

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